Day 58: Wednesday 11/16/11

EVERYDAY MATH

Today students did a brief review with Mr. Hartwell and took a small quiz.  The quiz is designed to help students prepare for the final unit 3 test.  After the quiz, students worked independently to complete their guided notes.  Today's periods were all shortened due to parent conferences.

EDM Agenda

1.  Review

2.  Quiz

3.  Guided Notes

4.  Homework:  Watch this video on the Distributive Property.  Next, earn a proficient doing the distributive property and complete these questions.

PRE-ALGEBRA

Today students reviewed their chapter 4 review homework from last night.  Next, they took the first half of their chapter 4 test.  We will take the second half tomorrow because the math periods are shortened Wednesday and Thursday due to conferences.  The homework for tonight is to watch this video and study for the test.

PRE Agenda
1.  Homework Review
2.  Chapter 4 Test
3.  Homework:  Video and Study

Photograph by Cole 11/15/11 7:35AM Troy Intermediate

One of my students has seen an albino deer roaming the fields around Troy recently (see his picture, above).  This is a very rare animal.  According to this website about one in 100,000 fawn births are albino.  The deer may also be piebald, which are also very rare.  Therefore:

(n/100,000) = a

Where "n" is the number of deer in a region, "a" is the predicted number of albino deer.  The sentence above is an algebraic equation.  If I can approximate the number of deer living in Avon Lake, I can calculate the likely number of albino deer in the region.

According to this website the ideal holding capacity for deer in Northeast Ohio is about 30 deer per square mile.  I can express this as an equation as well:

30(m) = i

Where "m" is the square miles of a given location and "i" is the ideal holding capacity of deer for that given location.   Avon Lake is 11.1 square miles.

According to this website deer populations can increase as much as 82% in a year.  Using this fact, I can write this algebraic equation:

0.82(x) + x= y

Where "x" is the original deer population and "y" is the maximum deer population the following year.

A Couple of Questions:

• What is the "ideal" deer population of Avon Lake?
• If Avon Lake hosts the "ideal" number deer, how many albino deer would we predict to live in Avon Lake?
• If Avon Lake hosts the "ideal" number of deer one year and they enjoy the maximum amount of population growth in one year, what will the population be the following year (given that none die)?

Another picture taken by an Avon Lake student November 2011.